Используйте metaflac для переименования .flac файлов от тегов flac рекурсивно

Я нашел сценарий Python записанным Louis-Philippe Véronneau.

Актуальный код может быть найден на его репозитории мерзавца: https://gitlab.com/baldurmen/rename-flac

Необходимо установить python-docopt (sudo склонный - получают python-docopt установки), и запустите этот скрипт после Вас, chmod +x переименовывают-flac.py его:

#!/usr/bin/python

"""
rename-flac takes the information from FLAC metadata to batch rename
the files according to a filenaming scheme.

Usage:
    rename-flac.py [--verbose] <scheme> <directory>
    rename-flac.py (-h | --help)
    rename-flac.py --version

Arguments:
    <scheme>         The filenaming scheme. Has to be between quotation marks
    <directory>      The path to the directory containing the album

Options:
    -h  --help       Shows the help screen
    --version        Outputs version information
    --verbose        Runs the program as verbose mode

    These are the options you can use to define the filenaming scheme:
      %a = Artist  |   %b = Album         |   %d = Date
      %g = Genre   |   %n = Tracknumber   |   %t = Title
"""
import sys

try:
    from docopt import docopt  # Creating command-line interface
except ImportError:
    sys.stderr.write("""
        %s is not installed: this program won't run correctly.
        To install %s, run: aptitude install %s
        """ % ("python-docopt", "python-docopt", "python-docopt"))

import subprocess
import re
import os


TAGS = dict(a='artist', b='album', d='date',
            g='genre', n='tracknumber', t='title')


# Defining the function that fetches metadata and formats it
def metadata(filepath): 
    args = ["--show-tag=%s" % tag for tag in TAGS.values()]
    tags = ["%s=" % tag for tag in TAGS.values()]
    formatter = dict()
    pipe = subprocess.Popen(["metaflac"] + args + [filepath],
                            stdout=subprocess.PIPE)
    output, error = pipe.communicate()
    if pipe.returncode:
        raise IOError("metaflac failed: %s" % error)
    output = output.splitlines()
    for tag in tags:
        for item in output:
            x = re.compile(re.escape(tag), re.IGNORECASE)
            if bool(re.match(x, item)) ==  True:
                tag = tag.replace("=", "")
                if tag == "tracknumber":
                    formatter[tag] = x.sub("", item).zfill(2)
                else:
                    formatter[tag] = x.sub("", item)
    return formatter


# Defining function that renames the files
def rename(scheme, dirname, filename, args):
    filepath = os.path.join(dirname, filename)
    new_filename = scheme % metadata(filepath) + ".flac"
    if new_filename == filename:
        if args["--verbose"] == True:
            print("%s is already named correctly") % (filename)
    else:
        new_filepath = os.path.join(dirname, new_filename)
        os.rename(filepath, new_filepath)
        if args["--verbose"] == True:
            print("%s >> %s") % (filename, new_filename)


# Defining main function
def main():
    args = docopt(__doc__, version="rename-flac 1.0")
    scheme = args["<scheme>"]
    if not re.search("%[tn]", scheme):  # To have a unique filename
        sys.stderr.write("%t or %n has to be present in <scheme>\n")
        return
    scheme = re.sub('%%([%s])' % ''.join(TAGS.keys()),
                lambda m: '%%(%s)s' % TAGS[m.group(1)],
                scheme)
    for dirname, _, filenames in os.walk(
                                   args["<directory>"],
                                   topdown=False):
        for filename in filenames:
            if os.path.splitext(filename)[1] == ".flac":
                try:
                    rename(scheme, dirname, filename, args)
                except KeyboardInterrupt:
                    raise
                except OSError:
                    print("Song title contains /. Please rename it")


# Calling main function
if __name__ == "__main__":
    main()

Я протестировал его, и все работает как очарование!Спасибо!